Integrand size = 27, antiderivative size = 124 \[ \int \cot ^5(c+d x) \csc (c+d x) (a+b \sin (c+d x))^2 \, dx=-\frac {\left (a^2-2 b^2\right ) \csc (c+d x)}{d}+\frac {2 a b \csc ^2(c+d x)}{d}+\frac {\left (2 a^2-b^2\right ) \csc ^3(c+d x)}{3 d}-\frac {a b \csc ^4(c+d x)}{2 d}-\frac {a^2 \csc ^5(c+d x)}{5 d}+\frac {2 a b \log (\sin (c+d x))}{d}+\frac {b^2 \sin (c+d x)}{d} \]
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Time = 0.11 (sec) , antiderivative size = 124, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.111, Rules used = {2916, 12, 962} \[ \int \cot ^5(c+d x) \csc (c+d x) (a+b \sin (c+d x))^2 \, dx=\frac {\left (2 a^2-b^2\right ) \csc ^3(c+d x)}{3 d}-\frac {\left (a^2-2 b^2\right ) \csc (c+d x)}{d}-\frac {a^2 \csc ^5(c+d x)}{5 d}-\frac {a b \csc ^4(c+d x)}{2 d}+\frac {2 a b \csc ^2(c+d x)}{d}+\frac {2 a b \log (\sin (c+d x))}{d}+\frac {b^2 \sin (c+d x)}{d} \]
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Rule 12
Rule 962
Rule 2916
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int \frac {b^6 (a+x)^2 \left (b^2-x^2\right )^2}{x^6} \, dx,x,b \sin (c+d x)\right )}{b^5 d} \\ & = \frac {b \text {Subst}\left (\int \frac {(a+x)^2 \left (b^2-x^2\right )^2}{x^6} \, dx,x,b \sin (c+d x)\right )}{d} \\ & = \frac {b \text {Subst}\left (\int \left (1+\frac {a^2 b^4}{x^6}+\frac {2 a b^4}{x^5}+\frac {-2 a^2 b^2+b^4}{x^4}-\frac {4 a b^2}{x^3}+\frac {a^2-2 b^2}{x^2}+\frac {2 a}{x}\right ) \, dx,x,b \sin (c+d x)\right )}{d} \\ & = -\frac {\left (a^2-2 b^2\right ) \csc (c+d x)}{d}+\frac {2 a b \csc ^2(c+d x)}{d}+\frac {\left (2 a^2-b^2\right ) \csc ^3(c+d x)}{3 d}-\frac {a b \csc ^4(c+d x)}{2 d}-\frac {a^2 \csc ^5(c+d x)}{5 d}+\frac {2 a b \log (\sin (c+d x))}{d}+\frac {b^2 \sin (c+d x)}{d} \\ \end{align*}
Time = 0.13 (sec) , antiderivative size = 105, normalized size of antiderivative = 0.85 \[ \int \cot ^5(c+d x) \csc (c+d x) (a+b \sin (c+d x))^2 \, dx=\frac {-30 \left (a^2-2 b^2\right ) \csc (c+d x)+60 a b \csc ^2(c+d x)+10 \left (2 a^2-b^2\right ) \csc ^3(c+d x)-15 a b \csc ^4(c+d x)-6 a^2 \csc ^5(c+d x)+30 b (2 a \log (\sin (c+d x))+b \sin (c+d x))}{30 d} \]
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Time = 0.47 (sec) , antiderivative size = 115, normalized size of antiderivative = 0.93
method | result | size |
derivativedivides | \(-\frac {\frac {\left (\csc ^{5}\left (d x +c \right )\right ) a^{2}}{5}+\frac {a b \left (\csc ^{4}\left (d x +c \right )\right )}{2}-\frac {2 a^{2} \left (\csc ^{3}\left (d x +c \right )\right )}{3}+\frac {b^{2} \left (\csc ^{3}\left (d x +c \right )\right )}{3}-2 a b \left (\csc ^{2}\left (d x +c \right )\right )+\csc \left (d x +c \right ) a^{2}-2 \csc \left (d x +c \right ) b^{2}-\frac {b^{2}}{\csc \left (d x +c \right )}+2 a b \ln \left (\csc \left (d x +c \right )\right )}{d}\) | \(115\) |
default | \(-\frac {\frac {\left (\csc ^{5}\left (d x +c \right )\right ) a^{2}}{5}+\frac {a b \left (\csc ^{4}\left (d x +c \right )\right )}{2}-\frac {2 a^{2} \left (\csc ^{3}\left (d x +c \right )\right )}{3}+\frac {b^{2} \left (\csc ^{3}\left (d x +c \right )\right )}{3}-2 a b \left (\csc ^{2}\left (d x +c \right )\right )+\csc \left (d x +c \right ) a^{2}-2 \csc \left (d x +c \right ) b^{2}-\frac {b^{2}}{\csc \left (d x +c \right )}+2 a b \ln \left (\csc \left (d x +c \right )\right )}{d}\) | \(115\) |
parallelrisch | \(\frac {-384 \ln \left (\sec ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a b +384 \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a b +\left (a^{2} \left (\sec ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) \left (\cos \left (2 d x +2 c \right )-\frac {3 \cos \left (4 d x +4 c \right )}{4}-\frac {29}{20}\right ) \left (\csc ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-\frac {39 b \left (\cos \left (2 d x +2 c \right )+\frac {19 \cos \left (4 d x +4 c \right )}{52}-\frac {7}{52}\right ) \sec \left (\frac {d x}{2}+\frac {c}{2}\right ) a \csc \left (\frac {d x}{2}+\frac {c}{2}\right )}{8}-36 b^{2} \left (\cos \left (2 d x +2 c \right )-\frac {\cos \left (4 d x +4 c \right )}{12}-\frac {25}{36}\right )\right ) \left (\csc ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) \left (\sec ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{192 d}\) | \(180\) |
risch | \(-2 i x a b -\frac {i b^{2} {\mathrm e}^{i \left (d x +c \right )}}{2 d}+\frac {i {\mathrm e}^{-i \left (d x +c \right )} b^{2}}{2 d}-\frac {4 i a b c}{d}-\frac {2 i \left (15 a^{2} {\mathrm e}^{9 i \left (d x +c \right )}-30 b^{2} {\mathrm e}^{9 i \left (d x +c \right )}-20 a^{2} {\mathrm e}^{7 i \left (d x +c \right )}+100 b^{2} {\mathrm e}^{7 i \left (d x +c \right )}-60 i a b \,{\mathrm e}^{8 i \left (d x +c \right )}+58 a^{2} {\mathrm e}^{5 i \left (d x +c \right )}-140 b^{2} {\mathrm e}^{5 i \left (d x +c \right )}+120 i a b \,{\mathrm e}^{6 i \left (d x +c \right )}-20 a^{2} {\mathrm e}^{3 i \left (d x +c \right )}+100 b^{2} {\mathrm e}^{3 i \left (d x +c \right )}-120 i a b \,{\mathrm e}^{4 i \left (d x +c \right )}+15 a^{2} {\mathrm e}^{i \left (d x +c \right )}-30 b^{2} {\mathrm e}^{i \left (d x +c \right )}+60 i a b \,{\mathrm e}^{2 i \left (d x +c \right )}\right )}{15 d \left ({\mathrm e}^{2 i \left (d x +c \right )}-1\right )^{5}}+\frac {2 a b \ln \left ({\mathrm e}^{2 i \left (d x +c \right )}-1\right )}{d}\) | \(288\) |
norman | \(\frac {-\frac {a^{2}}{160 d}-\frac {a^{2} \left (\tan ^{14}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{160 d}-\frac {5 \left (17 a^{2}-88 b^{2}\right ) \left (\tan ^{6}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{96 d}-\frac {5 \left (17 a^{2}-88 b^{2}\right ) \left (\tan ^{8}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{96 d}+\frac {\left (19 a^{2}-20 b^{2}\right ) \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{480 d}+\frac {\left (19 a^{2}-20 b^{2}\right ) \left (\tan ^{12}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{480 d}-\frac {\left (103 a^{2}-380 b^{2}\right ) \left (\tan ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{480 d}-\frac {\left (103 a^{2}-380 b^{2}\right ) \left (\tan ^{10}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{480 d}-\frac {11 a b \left (\tan ^{7}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{16 d}-\frac {a b \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{32 d}+\frac {5 a b \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{16 d}+\frac {5 a b \left (\tan ^{11}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{16 d}-\frac {a b \left (\tan ^{13}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{32 d}}{\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{5} \left (1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )^{2}}+\frac {2 a b \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d}-\frac {2 a b \ln \left (1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d}\) | \(345\) |
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Time = 0.40 (sec) , antiderivative size = 166, normalized size of antiderivative = 1.34 \[ \int \cot ^5(c+d x) \csc (c+d x) (a+b \sin (c+d x))^2 \, dx=-\frac {30 \, b^{2} \cos \left (d x + c\right )^{6} + 30 \, {\left (a^{2} - 5 \, b^{2}\right )} \cos \left (d x + c\right )^{4} - 40 \, {\left (a^{2} - 5 \, b^{2}\right )} \cos \left (d x + c\right )^{2} - 60 \, {\left (a b \cos \left (d x + c\right )^{4} - 2 \, a b \cos \left (d x + c\right )^{2} + a b\right )} \log \left (\frac {1}{2} \, \sin \left (d x + c\right )\right ) \sin \left (d x + c\right ) + 16 \, a^{2} - 80 \, b^{2} + 15 \, {\left (4 \, a b \cos \left (d x + c\right )^{2} - 3 \, a b\right )} \sin \left (d x + c\right )}{30 \, {\left (d \cos \left (d x + c\right )^{4} - 2 \, d \cos \left (d x + c\right )^{2} + d\right )} \sin \left (d x + c\right )} \]
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Timed out. \[ \int \cot ^5(c+d x) \csc (c+d x) (a+b \sin (c+d x))^2 \, dx=\text {Timed out} \]
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Time = 0.19 (sec) , antiderivative size = 105, normalized size of antiderivative = 0.85 \[ \int \cot ^5(c+d x) \csc (c+d x) (a+b \sin (c+d x))^2 \, dx=\frac {60 \, a b \log \left (\sin \left (d x + c\right )\right ) + 30 \, b^{2} \sin \left (d x + c\right ) + \frac {60 \, a b \sin \left (d x + c\right )^{3} - 30 \, {\left (a^{2} - 2 \, b^{2}\right )} \sin \left (d x + c\right )^{4} - 15 \, a b \sin \left (d x + c\right ) + 10 \, {\left (2 \, a^{2} - b^{2}\right )} \sin \left (d x + c\right )^{2} - 6 \, a^{2}}{\sin \left (d x + c\right )^{5}}}{30 \, d} \]
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Time = 0.40 (sec) , antiderivative size = 131, normalized size of antiderivative = 1.06 \[ \int \cot ^5(c+d x) \csc (c+d x) (a+b \sin (c+d x))^2 \, dx=\frac {60 \, a b \log \left ({\left | \sin \left (d x + c\right ) \right |}\right ) + 30 \, b^{2} \sin \left (d x + c\right ) - \frac {137 \, a b \sin \left (d x + c\right )^{5} + 30 \, a^{2} \sin \left (d x + c\right )^{4} - 60 \, b^{2} \sin \left (d x + c\right )^{4} - 60 \, a b \sin \left (d x + c\right )^{3} - 20 \, a^{2} \sin \left (d x + c\right )^{2} + 10 \, b^{2} \sin \left (d x + c\right )^{2} + 15 \, a b \sin \left (d x + c\right ) + 6 \, a^{2}}{\sin \left (d x + c\right )^{5}}}{30 \, d} \]
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Time = 11.41 (sec) , antiderivative size = 297, normalized size of antiderivative = 2.40 \[ \int \cot ^5(c+d x) \csc (c+d x) (a+b \sin (c+d x))^2 \, dx=\frac {{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3\,\left (\frac {5\,a^2}{96}-\frac {b^2}{24}\right )}{d}-\frac {\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\,\left (\frac {5\,a^2}{16}-\frac {7\,b^2}{8}\right )}{d}-\frac {{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^6\,\left (10\,a^2-92\,b^2\right )-{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2\,\left (\frac {22\,a^2}{15}-\frac {4\,b^2}{3}\right )+{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4\,\left (\frac {25\,a^2}{3}-\frac {80\,b^2}{3}\right )+\frac {a^2}{5}-11\,a\,b\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3-12\,a\,b\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^5+a\,b\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}{d\,\left (32\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^7+32\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^5\right )}-\frac {a^2\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^5}{160\,d}+\frac {3\,a\,b\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2}{8\,d}-\frac {a\,b\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4}{32\,d}+\frac {2\,a\,b\,\ln \left (\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\right )}{d}-\frac {2\,a\,b\,\ln \left ({\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2+1\right )}{d} \]
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